Published by:
CGP EDU Academic Team
Published on: September 13, 2026
A ball is dropped from a height of 20 m and rebounds with a velocity which is 3/4th of the velocity with which it hits the ground. What is the time interval between the first and second bounces (g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
A
V 1 = 
= 
= 20m/sec
V 2 = 
× 20 = 15m/sec
t 2 = 
= 
= 1.5 sec
total time = 2 × 1.5 = 3 sec
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